[Prolog] How do I implement recursion in Prolog?

To implement recursion in Prolog, you can define rules that call themselves until a certain condition is met. Here's an example of how to implement recursion in Prolog:

1% Define a base case for the recursion
2recursive_predicate(0).
3 
4% Define a rule that calls itself until the base case is met
5recursive_predicate(N) :-
6    N > 0,
7    Next is N - 1,
8    recursive_predicate(Next).

In this example, recursive_predicate is a predicate that takes an argument N. The base case is defined as when N equals 0. The recursive rule is defined as when N is greater than 0, it subtracts 1 from N and calls recursive_predicate again with the new value. This process continues until the base case is met.

You can then query the predicate with different values of N to see the recursive behavior. For example:

 1?- recursive_predicate(3).
 2true.
 3
 4?- recursive_predicate(5).
 5true.
 6
 7?- recursive_predicate(0).
 8true.
 9
10?- recursive_predicate(-1).
11false.

In this case, recursive_predicate(3) and recursive_predicate(5) are both true because 3 and 5 can be reduced to 0 through the recursive rule. On the other hand, recursive_predicate(0) is true because it matches the base case. Finally, recursive_predicate(-1) is false because it does not satisfy the conditions of the recursive rule or the base case.